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The COVID-19 :The recent Corona virus tragedy in China proposing to ask some questions. 1. Was this a bio weapon?If this is Bio Weapon then who made this? Is it china itself ? Was it a accidental failure or intentional to reduce the population? Was it sprade by other country to get business profit?   It is sure that it is not natural virus which get evolved and become deadly.Is there any past incident where a natural virus get evolved and become deadly in this short time? Now everyone try to find out antidote of this flue .Due to Corona effect many person infected and already many one lost their life(Actually we may not have proper figure .I am saying this as we all know how the whistle blower Chinese doctor Li Wenliang is treated by chinese government and also how do chinese reporters get missing. This incidents may be questioning authenticity of the death and infected persons figures. ),many one lost their job and actually they suffering many many problems lik...

Thirty-one years ago , Dick Feynamn told me about his 'sum over histories' version of Quantum Mechanics.'The electron does anything it likes',he said, 'It goes in any direction at any speed,forward or backward in time,however it likes, and then add up the amplitudes and it gives the wave-function'. 'I said to him,'You're crazy'. But he was't.                                                             - F.J Dyson

Thomas and Fermi independently developed  a theory of complex many electrons atom or ion by choosing fermi gas of electron in ground state.The electrons confined in space by a central potential V(r) where V(r) is zero for large distance(r) from the nucleus. Apart from this assumption they also assumed the variation of potential is very slow in distance very much larger than de'Broglie wavelengths of electron and the thermal energy kT is much smaller than the potential energy in the boundary of the atom.In the near of nucleas potential remain constant .And for large distance its value is zero.Then Schrödinger equation becomes $$\frac{-\hbar^2\nabla^2\Psi}{2m}=E\Psi$$ Which solution gives $$\Psi=C\sin\left({k_x x}\right)\sin\left({k_y y}\right)\sin\left({k_z z}\right)$$ $$k^2=\frac{2mE}{\hbar^2}={k_x}^2+{k_y}^2+{k_z}^2$$ Where we are using the boundary conditions $$\Psi(x,y,0)=\Psi(x,y,L)=\Psi(x,0,z)=\Psi(x,L,z)=\Psi(0,y,z)=\Psi(L,y,z)=0$$ where the solution confined in a ...

The Einstien's mass-energy dispersion relation be$$E^2=c^2P^2+{m_0}^2c^4\space\space(1)$$ Now in Quantum mechanics $$E\rightarrow i\hbar\frac{\partial}{\partial t} \Rightarrow E^2 \rightarrow -\hbar^2\frac{\partial^2}{\partial t^2}$$and $$P\rightarrow -i\hbar\nabla\Rightarrow P^2\rightarrow -\hbar^2 \nabla^2$$ In this fashion we can write $$ -\hbar^2\frac{\partial^2}{\partial t^2}\psi=-\hbar^2c^2 \nabla^2\psi+{m_0}^2c^4$$ $$\Rightarrow  \frac{1}{c^2}\frac{\partial^2}{\partial t^2}\psi-\nabla^2\psi+\frac{{m_0}^2c^2}{\hbar^2}\psi=0\Rightarrow \Box\psi+\frac{{m_0}^2c^2}{\hbar^2}\psi=0$$ This is the Klein-Gordon  equation. This equation solutions  is $$Ae^\frac{i p^\mu x_\mu}{\hbar}=Ae^\frac{i \left(Et-\mathbf{p\cdot x}\right)}{\hbar}$$ Where A is a normalization constant. Now substituting this solution imto Klein-Gordon  equation gives $$E^2=c^2P^2+{m_0}^2c^4\Rightarrow E=\pm\sqrt{c^2P^2+{m_0}^2c^4}$$Therefore Klein-Gordon equation gives negative energy solu...

The Maxwell's  equations are $$(1)\nabla\cdot\mathbf{E}=\frac{\rho}{\epsilon_0}$$ $$(2)\nabla\cdot\mathbf{B}=0$$ $$(3)\nabla \times\mathbf{E}=-\frac{\partial \mathbf{B}}{\partial t}$$ $$(4)\nabla \times\mathbf{B}=-\mu_0\epsilon_0\frac{\partial \mathbf{E}}{\partial t}+\mu_0\mathbf{J}$$ From (3) we get: $$\nabla\times\mathbf{E}=-\frac{\partial}{\partial t}(\nabla\times\mathbf{A})[\because \mathbf{B}=\nabla\times\mathbf{A}]\Rightarrow\nabla\times \left(\mathbf{E}+\frac{\partial\mathbf{A}}{\partial t}\right )=0$$$$\Rightarrow\mathbf{E}+\frac{\partial\mathbf{A}}{\partial t}=-\nabla\phi\Rightarrow\mathbf{E}= -\left(\frac{\partial\mathbf{A}}{\partial t}+\nabla\phi\right)$$ Now electromagnetic field tensor defined as $$F^{\mu\nu}=\partial ^{\nu}A^{\mu}-\partial ^{\mu}A^{\nu}=\frac{\partial A^{\mu}}{\partial x_{\nu}}-\frac{\partial A^\nu}{\partial x_{\mu}}$$   Electromagnetic  Four  Potential  $$ \space A^{\mu\nu}=\{\frac{\phi}{c},A_x,A_y,A_z\}$$ $$F^{00}=...

Four Vector : $$x^{\mu}=\{ct,\overrightarrow{\mathbf{r}}\}$$$$x_{\mu} = \{ct,-\overrightarrow{\mathbf{r}}\}$$ Four Momentum : $$p^{\mu}=\{\frac{E}{c},\overrightarrow{\mathbf{p}}\}$$$$p_{\mu}=\{{\frac{E}{c}},-\overrightarrow{\mathbf{p}}\}$$ Four Potential : $$A^{\mu}=\{\phi,\overrightarrow{\mathbf{A}}\}$$$$A_{\mu}=\{{\phi},-\overrightarrow{\mathbf{A}}\}$$ Four Current : $$j^{\mu}=\{c\rho,\overrightarrow{\mathbf{J}}\}$$$$j_{\mu}=\{c\rho,-\overrightarrow{\mathbf{J}}\}$$ More Details click  here [PDF]

Basic Ubuntu Command may all linux user know 1.😎sudo apt-get update: to update the cache 2.sudo apt-get upgrade: to upgrade package 2.sudo apt-get autoclean: to cleaning the breaking package 3.sudo apt-get autoremove: to removing the the breaking packges 4.pwd :to know the present working directory 5.cd:to go in the user directory 6.cd address_of_a_directory:to change present directory 7.ls:to get the contents info of thepresent directory 8.mkdir dir_name:to make a directory inside of present directory with name dir_name 9.touch test_file:to make a empty file inside of present directory with name test_file 10.sudo su:to change in super user to change protected files andd directory 11.rm -r file_name:to remove a file with name file_name 12.rm -r dir_name:to remove a directory 13.sudo chmod+xug file/dir:to change mode of a file or a directory 14.sudo chown        :to change file or directory ownership 15.sudo nautilus :to open,edit an...